(x^2)+4(10x)=10

Solution for (x^2)+4(10x)=10 equation:

(x^2)+4(10x)=10

We move all terms to the left:

(x^2)+4(10x)-(10)=0

a = 1; b = 410; c = -10;
Δ = b2-4ac
Δ = 4102-4·1·(-10)
Δ = 168140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{168140}=\sqrt{4*42035}=\sqrt{4}*\sqrt{42035}=2\sqrt{42035}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(410)-2\sqrt{42035}}{2*1}=\frac{-410-2\sqrt{42035}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(410)+2\sqrt{42035}}{2*1}=\frac{-410+2\sqrt{42035}}{2}
$